Class 7 maths · Original EZT practice
RS Aggarwal Class 7: original worked practice
A wrong sign or a misplaced decimal can undo a good method. These practice pairs ask you to name the rule first, show the working and check whether the answer makes sense.
This page gives Class 7 students 12 original worked examples and 12 fresh self-check questions with explained answers. Use the EZT practice-skill index alongside your RS Aggarwal book to learn a method, not to look up its exercise answers.
Original EZT practice, not copied textbook exercises or a full-solutions service. Match the topic to your own book; editions vary. This is not an official chapter index, exercise map or claim about your current syllabus. Follow your school's topic list.
Bharati Bhawan lists Mathematics for Class 7 by R S Aggarwal. It also lists a separate Class 7 Book 1 title. These sources identify the books, not the order of our practice topics. EZ Tuitions is not affiliated with the authors or publisher.
Choose, solve, check, then try a fresh question.
Before calculating, read the method prompt and name the condition that makes it useful. Write your own attempt. Open the steps only when you need them, and use the check to catch a wrong sign, unit or interpretation. Finish with the fresh question before reading its answer.
Brackets and equal-priority operations
Choose the method: Resolve brackets first. Multiplication and division have equal priority and run left to right.
EZT practice question
Without a calculator, evaluate 45 - 3 × (4 + 5).
Show the worked solution
- The bracket is 4 + 5 = 9.
- Multiply before subtracting: 3 × 9 = 27.
- Subtract: 45 - 27 = 18.
Answer: 18
Check: The subtraction removes less than 45, so a positive result smaller than 45 is reasonable.
Watch for this: Subtracting 3 from 45 first changes the expression.
Now try it yourself
Evaluate 6 + 24 ÷ 3 × 2.
Check your answer
22
Divide and multiply left to right: 24 ÷ 3 × 2 = 8 × 2 = 16. Then 6 + 16 = 22. Doing 3 × 2 first would change the grouping.
Adding and subtracting decimals
Choose the method: Line up place values, using zeros as placeholders when helpful.
EZT practice question
A ribbon is 1.75 m long. Another 0.6 m is joined to it, then 0.08 m is cut off. Find the remaining length.
Show the worked solution
- Write the lengths with matching decimal places: 1.75, 0.60 and 0.08.
- The combined length is 1.75 + 0.60 = 2.35 m.
- After cutting, 2.35 - 0.08 = 2.27 m.
Answer: 2.27 m
Check: The net change is 0.52 m, and 1.75 + 0.52 = 2.27.
Watch for this: Treating 0.6 as 0.06 confuses tenths with hundredths.
Now try it yourself
Find 4.2 - 0.95.
Check your answer
3.25
Write 4.2 as 4.20. Then 4.20 - 0.95 = 3.25. Adding 0.95 back gives 4.20.
Fractions need a common unit
Choose the method: Use equivalent fractions with a common denominator before combining numerators.
EZT practice question
Calculate 3/4 - 2/5 and give the answer in simplest form.
Show the worked solution
- The least common denominator is 20.
- Rewrite 3/4 = 15/20 and 2/5 = 8/20.
- Subtract the numerators: 15/20 - 8/20 = 7/20.
Answer: 7/20
Check: The result 0.35 is positive and smaller than 3/4.
Watch for this: Subtracting denominators gives a different operation, not the difference of fractions.
Now try it yourself
Find 5/6 + 1/4 in simplest form.
Check your answer
13/12, or 1 1/12
Use twelfths: 10/12 + 3/12 = 13/12. The sum is slightly greater than 1.
Expressions from a pattern rule
Choose the method: Name the changing quantity and keep any fixed addition separate.
EZT practice question
A tile strip uses 3 tiles for each coloured block and 2 end tiles in total. Write the total T for n blocks, then find T when n = 7.
Show the worked solution
- The n coloured blocks use 3n tiles.
- The two end tiles are added once, so T = 3n + 2.
- At n = 7, T = 3 × 7 + 2 = 23.
Answer: T = 3n + 2; 23 tiles
Check: Increasing n by 1 adds exactly 3 tiles, while the 2 end tiles stay fixed.
Watch for this: 3(n + 2) counts 6 end tiles instead of 2.
Now try it yourself
A rectangle has length l and breadth b. Write its perimeter P, then use l = 8 cm and b = 3 cm.
Check your answer
P = 2l + 2b; 22 cm
There are two lengths and two breadths. So P = 2 × 8 + 2 × 3 = 22 cm.
Signs in integer operations
Choose the method: Subtracting a negative adds its opposite; multiplication has its own sign rule.
EZT practice question
Evaluate -8 + 13 - (-4).
Show the worked solution
- First, -8 + 13 = 5.
- Subtracting -4 is the same as adding 4.
- The final result is 5 + 4 = 9.
Answer: 9
Check: From -8, a move 13 to the right reaches 5, then a move 4 to the right reaches 9.
Watch for this: The final operation is not 5 - 4 because the number being subtracted is negative.
Now try it yourself
Evaluate (-6) × (-3) - 5.
Check your answer
13
A negative times a negative is positive, so the product is 18. Then 18 - 5 = 13.
Name the angle relationship
Choose the method: Use corresponding angles only when the two lines are parallel.
EZT practice question
Two parallel lines are cut by a transversal. One angle is 68°. Find its corresponding angle and the adjacent angle that forms a straight angle with it.
Show the worked solution
- Corresponding angles between parallel lines are equal, so the corresponding angle is 68°.
- The specified adjacent angle and 68° form 180°.
- The adjacent angle is 180° - 68° = 112°.
Answer: Corresponding 68°; adjacent 112°
Check: 68° + 112° = 180°. Only the stated adjacent straight-angle pair is being added.
Watch for this: Adjacent angles are not always supplementary; the straight-line condition matters.
Now try it yourself
Two lines intersect. An angle is 47°. Find its vertically opposite angle and one adjacent angle.
Check your answer
Vertically opposite 47°; adjacent 133°
Vertically opposite angles are equal. The adjacent straight-line pair totals 180°, so 180° - 47° = 133°.
Inside and outside triangle angles
Choose the method: Distinguish the 180° angle sum inside a triangle from the exterior-angle relationship.
EZT practice question
Two interior angles of a triangle are 52° and 63°. Find its third interior angle.
Show the worked solution
- The three interior angles of a triangle sum to 180°.
- The two known angles total 52° + 63° = 115°.
- The missing angle is 180° - 115° = 65°.
Answer: 65°
Check: 52° + 63° + 65° = 180°.
Watch for this: The missing interior angle is not the sum of the other two.
Now try it yourself
An exterior angle of a triangle is 124°. One of its two remote interior angles is 57°. Find the other remote interior angle.
Check your answer
67°
An exterior angle equals the sum of its two remote interior angles. So 124° - 57° = 67°.
Powers count equal factors
Choose the method: The exponent counts repeated factors, not repeated addition.
EZT practice question
Write 3 × 3 × 3 × 3 as a power and evaluate it.
Show the worked solution
- There are four equal factors of 3.
- The power is 3⁴.
- Pair the factors: 9 × 9 = 81.
Answer: 3⁴ = 81
Check: 3⁴ is larger than 3³ = 27 by a factor of 3.
Watch for this: 3 × 4 = 12 is repeated addition, not this repeated multiplication.
Now try it yourself
Evaluate 2⁵ × 2³.
Check your answer
256
There are 5 + 3 = 8 factors of 2, so 2⁸ = 256. The exponents add when multiplying powers with the same base.
A common factor is not a common multiple
Choose the method: Choose LCM for a first shared repeat and HCF for a largest equal grouping.
EZT practice question
Two bells ring every 12 minutes and 18 minutes. They ring together now. After how many minutes will they next ring together?
Show the worked solution
- The next shared ringing time is the least common multiple of 12 and 18.
- 12 = 2² × 3 and 18 = 2 × 3².
- LCM = 2² × 3² = 36 minutes.
Answer: 36 minutes
Check: 36 ÷ 12 = 3 and 36 ÷ 18 = 2; neither 12 nor 18 is divisible by both.
Watch for this: The common factor 6 does not represent a time when both full intervals have elapsed.
Now try it yourself
Find the HCF of 42 and 56.
Check your answer
14
42 = 2 × 3 × 7 and 56 = 2³ × 7. Their common prime factors give 2 × 7 = 14.
Dividing by a fraction counts pieces
Choose the method: Ask how many pieces of the divisor fit into the starting quantity.
EZT practice question
How many 1/8-litre cups can be filled from 3/4 litre, with no spillage?
Show the worked solution
- Express 3/4 litre as 6/8 litre.
- Each cup holds 1/8 litre.
- Six such portions fit, so(3/4) ÷ (1/8) = 6.
Answer: 6 cups
Check: 6 × (1/8) = 6/8 = 3/4 litre.
Watch for this: Multiplying 3/4 by 1/8 answers a different question.
Now try it yourself
Find 2/3 of 9/10 in simplest form.
Check your answer
3/5
Multiply the fractions: 18/30 = 3/5. It is smaller than 9/10 because only two thirds is taken.
Keep magnitude in decimal multiplication
Choose the method: Estimate the size first, then place the decimal using place value.
EZT practice question
Find 2.4 × 1.5.
Show the worked solution
- Since 1.5 is one and a half, the answer should be greater than 2.4 but less than 4.8.
- Multiply 24 × 15 = 360.
- The original factors contain two decimal places in total, so the product is 3.60 = 3.6.
Answer: 3.6
Check: Half of 2.4 is 1.2, and 2.4 + 1.2 = 3.6.
Watch for this: 36 is too large for the original factors; an estimate catches the misplaced decimal.
Now try it yourself
Find 4.5 ÷ 0.3.
Check your answer
15
Multiply both numbers by 10 to make 45 ÷ 3 = 15. Check 15 × 0.3 = 4.5.
Undo operations and check the result
Choose the method: Do the same operation to both sides to preserve equality.
EZT practice question
Solve 5x - 7 = 28.
Show the worked solution
- Add 7 to both sides: 5x = 35.
- Divide both sides by 5: x = 7.
- Substitute 7 into the original: 5 × 7 - 7 = 28.
Answer: x = 7
Check: The substitution gives the required right-hand side 28.
Watch for this: Changing only one side would no longer preserve the same equation.
Now try it yourself
Solve 3(y + 2) = 27.
Check your answer
y = 7
Divide both sides by 3: y + 2 = 9. Subtract 2: y = 7. Check 3(7 + 2) = 27.
Know the rule but lose track of the steps?
Bring your Class 7 maths book, your school topic list and a question you attempted. Ask a tutor to explain the choice of method and test it with a different problem. Agree the lesson topics, schedule and fee before starting.
For subject-focused support, see maths tuition. Agree the topics, schedule and fee with your chosen tutor.
Questions about this practice page
- Are these the official RS Aggarwal Class 7 exercise solutions?
- No. These are original EZT practice questions with worked steps and fresh self-check questions. They are not reproduced textbook questions, an exercise-number answer key or an official publisher resource.
- Why is the practice index not in chapter order?
- The publisher lists more than one Class 7 title, and editions vary. This page groups selected skills for practice; it does not claim a verified table of contents or exercise map. Match a skill to your own book and school topic list.
- How should I use the worked examples?
- Try the question before opening the steps. Name the method, calculate with units where needed, then use the check to test the result. Solve the fresh question before reading its explained answer.
- Does this page cover my full Class 7 maths syllabus?
- No. It covers selected arithmetic, algebra and angle skills. Your school may use a different sequence or require other topics. Use your teacher's topic list rather than treating this practice page as a complete course.
- What should I show a tutor if I keep getting an answer wrong?
- Bring your own attempted steps, the question and your book. Point to the first step you do not understand. Ask the tutor to explain the rule and set a different problem so you can test it. Agree lesson topics, schedule and fee before starting.